Discussion Detail - XAZXOJ

题解
元旦赛智慧数规律解5：32
retun 0 LV 10 @ 2024-1-2 20:31:10

#include <bits/stdc++.h>
using namespace std;

void PRC(int N)
{
	if(N==1) cout<<3;
	else if(N==2) cout<<5;
	else
	 {
	 	int N2, r;
	 	N2=(N-1)/3;
	 	r=N-1-N2*3;
	 	int a[3]={4*N2+4, 4*(N2+1)+1, 4*(N2+1)+3};
	 	cout<<a[r];
	 }
}

int main()
{
    int n;
	cin>>n;
	PRC(n);  
	return 0;
}

Eva LV 6 @ 2024-1-3 17:16:24

#include <bits/stdc++.h>
using namespace std;
int main()
{
int y,s,j,a;
int n;
cin >> n;
if(n==1 || n==2 || n==3)
{
if(n==1) cout<<3<<endl;
if(n==2)cout<<5<<endl;
if(n==3) cout<<7<<endl;
}
else
{
a = n-3;
//cout << a <<endl;
s = n / 3;
//s++;
//if (s==0) s=1;
//cout << s+1 << "组" <<endl;
//cout << s << "组" <<endl;
y = a % 3;
//cout << "第" << y << "个"<<endl;
if (y==1) j=0;
if (y==2) j=1;
if (y==0) j=-1;
//cout <<"加"<< j <<endl;
cout << 4*(s+1) + j <<endl;
}
return 0;
}
//3 5 7  bs
//8 9 11
//12 13 15
//16 17 19
//20 21 23
//24 25 27

规律解法